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/* (程序头部注释开始)

* 程序的版权和版本声明部分

* Copyright (c) 2011, 烟台大学计算机学院学生

* All rights reserved.

* 文件名称：定义分数类中<<和>>运算符重载，实现分数的输入输出，改造原程序中对运算结果显示方式，使程序读起来更自然。

* 作 者： 雷恒鑫

* 完成日期： 2012 年 04 月 14 日

* 版 本 号： V1.0

* 对任务及求解方法的描述部分

* 输入描述：

* 问题描述：

* 程序输出：

* 程序头部的注释结束

*/

#include<iostream.h>   
#include"stdlib.h"    int gcd(int m, int n);    class CFraction  
{  
private:  int nume;  // 分子  int deno;  // 分母  
public:  //构造函数及运算符重载的函数声明  CFraction(int nu=0,int de=1);   //构造函数，初始化用    void Simplify();                    //化简（使分子分母没有公因子）      void output();           //输出：以8/6为例，style为0时，输出8/6；    bool operator > (CFraction &t);    bool operator < (CFraction &t);    bool operator >= (CFraction &t);    bool operator <= (CFraction &t);    bool operator == (CFraction &t);    bool operator != (CFraction &t);    CFraction operator+(CFraction &c);     CFraction operator-(CFraction &c);  CFraction operator*(CFraction &c);    CFraction operator/(CFraction &c);  CFraction operator-();  friend ostream& operator << (ostream&,CFraction &);friend istream& operator >> (istream&,CFraction &);};  
istream& operator >> (istream& input,CFraction & c)
{ input>>c.nume>>c.deno;return input;
}
ostream& operator << (ostream& output,CFraction & c)
{output<<c.nume<<'/'<<c.deno<<endl; return output;
}
CFraction::CFraction(int nu,int de)   //构造函数，初始化用     
{  if (de!=0)    {    nume=nu;    deno=de;    }    else    {    cerr<<"初始化中发生错误，程序退出\n";        exit(0);    }    
}  
void CFraction::Simplify()                    //化简（使分子分母没有公因子）   
{   int n;  if(nume < 0)    {    n = gcd(-nume, deno);    }    else    {    n = gcd(nume, deno);    }    nume = nume / n;      deno = deno / n;  
}  
// 求m，n的最大公约数    
int gcd(int m, int n)    
{    int r;    if (m<n){r=m;m=n;n=r;}    while(r=m%n)  // 求m，n的最大公约数    {    m=n;    n=r;    }    return n;    
}    bool CFraction::operator > (CFraction &t)  
{  CFraction c2,c3;  c2.nume =nume*t.deno ;  c3.nume =t.nume *deno;  if(c2.nume >c3.nume )  return true;  else  return false;  
}  
bool CFraction::operator < (CFraction &t)   
{  CFraction c2,c3;  c2.nume =nume*t.deno ;  c3.nume =t.nume *deno;  if(c2.nume <c3.nume )  return true;  else  return false;  
}  
bool CFraction::operator >= (CFraction &t)  
{    CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1<t)    return false;    return true;    
}    bool CFraction::operator <= (CFraction &t)  
{    CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1>t)    return false;    return true;    
}    
bool CFraction::operator == (CFraction &t)   
{  CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1<t)    return false;    if (c1>t)    return false;    return false;  
}  bool CFraction::operator != (CFraction &t)  
{  CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1==t)    return false;  return true;  
}  
CFraction CFraction::operator+(CFraction &c)  
{  CFraction c2,c3,c4;  c2.nume =nume*c.deno ;  c3.nume =c.nume *deno;  c2.deno =deno*c.deno ;  c3.deno =c.deno *deno;  c4.nume=c2.nume +c3.nume ;  c4.deno =c2.deno ;  c4.Simplify ();  return c4;  
}  
CFraction CFraction::operator-(CFraction &c)  
{  CFraction c2,c3,c4;  c2.nume =nume*c.deno ;  c3.nume =c.nume *deno;  c2.deno =deno*c.deno ;  c3.deno =c.deno *deno;  c4.nume=c2.nume -c3.nume ;  c4.deno =c2.deno ;  c4.Simplify ();  return c4;  
}  
CFraction CFraction::operator*(CFraction &c)   
{  CFraction c2,c3,c4;  c2.nume =nume*c.nume  ;  c2.deno =deno*c.deno ;  c2.Simplify ();  return c2;  
}  
CFraction CFraction::operator/(CFraction &c)  
{  CFraction c2,c3;  c2.nume =c.deno ;  c2.deno =c.nume ;  c3.nume =nume*c2.nume ;  c3.deno =deno*c2.deno ;  c3.Simplify ();  return c3;  
}  
CFraction CFraction::operator-()  
{  CFraction c2;  c2.nume =nume;  c2.deno =deno;  c2.Simplify ();  if(c2.nume<0 || c2.deno<0)  {  if(c2.nume <0)  {  c2.nume =-nume;  }  else  {  c2.deno =-deno;  }  }  else  {  c2.nume =-nume;  c2.deno =deno;  }  return c2;  
}  //用于测试的main()函数  
void main()    
{    CFraction c1,c2,c;cout<<"请您输入一个分数c1：（以a b的形式输入）";cin>>c1;cout<<"请您输入一个分数c1：（以a b的形式输入）";cin>>c2;cout<<"c1为：";    cout<<c1;    cout<<"c2为：";    cout<<c2;    cout<<"下面比较两个时间大小：\n";    if (c1>c2) cout<<"c1>c2"<<endl;    if (c1<c2) cout<<"c1<c2"<<endl;    if (c1==c2) cout<<"c1＝c2"<<endl;     if (c1!=c2) cout<<"c1≠c2"<<endl;    if (c1>=c2) cout<<"c1≥c2"<<endl;    if (c1<=c2) cout<<"c1≤c2"<<endl;    cout<<endl;    cout<<"c1+c2的数值为：";    c=c1+c2;    cout<<c;  cout<<endl;  cout<<"c1-c2的数值为：";    c=c1-c2;    cout<<c;    cout<<endl;    cout<<"c1*c2的数值为：";    c=c1*c2;    cout<<c;  cout<<endl;  cout<<"c1/c2的数值为：";    c=c1/c2;    cout<<c;   cout<<endl;  cout<<"对c1取反的结果为：";  c=-c1;  cout<<c;  cout<<endl;     
}      

下面是改进后的程序：

#include<iostream.h>   
#include"stdlib.h"    int gcd(int m, int n);    class CFraction  
{  
private:  int nume;  // 分子  int deno;  // 分母 char unknown; // '/'的符号
public:  //构造函数及运算符重载的函数声明  CFraction(int nu=0,int de=1);   //构造函数，初始化用    void Simplify();                    //化简（使分子分母没有公因子）      void output();           //输出：以8/6为例，style为0时，输出8/6；    bool operator > (CFraction &t);    bool operator < (CFraction &t);    bool operator >= (CFraction &t);    bool operator <= (CFraction &t);    bool operator == (CFraction &t);    bool operator != (CFraction &t);    CFraction operator+(CFraction &c);     CFraction operator-(CFraction &c);  CFraction operator*(CFraction &c);    CFraction operator/(CFraction &c);  CFraction operator-();  friend ostream& operator << (ostream&,CFraction &);friend istream& operator >> (istream&,CFraction &);};  
istream& operator >> (istream& input,CFraction & c)
{ input>>c.nume>>c.unknown>>c.deno;return input;
}
ostream& operator << (ostream& output,CFraction & c)
{output<<c.nume<<'/'<<c.deno<<endl; return output;
}
CFraction::CFraction(int nu,int de)   //构造函数，初始化用     
{  if (de!=0)    {    nume=nu;    deno=de;    }    else    {    cerr<<"初始化中发生错误，程序退出\n";        exit(0);    }    
}  
void CFraction::Simplify()                    //化简（使分子分母没有公因子）   
{   int n;  if(nume < 0)    {    n = gcd(-nume, deno);    }    else    {    n = gcd(nume, deno);    }    nume = nume / n;      deno = deno / n;  
}  
// 求m，n的最大公约数    
int gcd(int m, int n)    
{    int r;    if (m<n){r=m;m=n;n=r;}    while(r=m%n)  // 求m，n的最大公约数    {    m=n;    n=r;    }    return n;    
}    bool CFraction::operator > (CFraction &t)  
{  CFraction c2,c3;  c2.nume =nume*t.deno ;  c3.nume =t.nume *deno;  if(c2.nume >c3.nume )  return true;  else  return false;  
}  
bool CFraction::operator < (CFraction &t)   
{  CFraction c2,c3;  c2.nume =nume*t.deno ;  c3.nume =t.nume *deno;  if(c2.nume <c3.nume )  return true;  else  return false;  
}  
bool CFraction::operator >= (CFraction &t)  
{    CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1<t)    return false;    return true;    
}    bool CFraction::operator <= (CFraction &t)  
{    CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1>t)    return false;    return true;    
}    
bool CFraction::operator == (CFraction &t)   
{  CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1<t)    return false;    if (c1>t)    return false;    return false;  
}  bool CFraction::operator != (CFraction &t)  
{  CFraction c1;    c1.nume =nume;  c1.deno =deno;  if (c1==t)    return false;  return true;  
}  
CFraction CFraction::operator+(CFraction &c)  
{  CFraction c2,c3,c4;  c2.nume =nume*c.deno ;  c3.nume =c.nume *deno;  c2.deno =deno*c.deno ;  c3.deno =c.deno *deno;  c4.nume=c2.nume +c3.nume ;  c4.deno =c2.deno ;  c4.Simplify ();  return c4;  
}  
CFraction CFraction::operator-(CFraction &c)  
{  CFraction c2,c3,c4;  c2.nume =nume*c.deno ;  c3.nume =c.nume *deno;  c2.deno =deno*c.deno ;  c3.deno =c.deno *deno;  c4.nume=c2.nume -c3.nume ;  c4.deno =c2.deno ;  c4.Simplify ();  return c4;  
}  
CFraction CFraction::operator*(CFraction &c)   
{  CFraction c2,c3,c4;  c2.nume =nume*c.nume  ;  c2.deno =deno*c.deno ;  c2.Simplify ();  return c2;  
}  
CFraction CFraction::operator/(CFraction &c)  
{  CFraction c2,c3;  c2.nume =c.deno ;  c2.deno =c.nume ;  c3.nume =nume*c2.nume ;  c3.deno =deno*c2.deno ;  c3.Simplify ();  return c3;  
}  
CFraction CFraction::operator-()  
{  CFraction c2;  c2.nume =nume;  c2.deno =deno;  c2.Simplify ();  if(c2.nume<0 || c2.deno<0)  {  if(c2.nume <0)  {  c2.nume =-nume;  }  else  {  c2.deno =-deno;  }  }  else  {  c2.nume =-nume;  c2.deno =deno;  }  return c2;  
}  //用于测试的main()函数  
void main()    
{    CFraction c1,c2,c;cout<<"请您输入一个分数c1：（以a/b的形式输入）";cin>>c1;cout<<"请您输入一个分数c1：（以a/b的形式输入）";cin>>c2;cout<<"c1为：";    cout<<c1;    cout<<"c2为：";    cout<<c2;    cout<<"下面比较两个时间大小：\n";    if (c1>c2) cout<<"c1>c2"<<endl;    if (c1<c2) cout<<"c1<c2"<<endl;    if (c1==c2) cout<<"c1＝c2"<<endl;     if (c1!=c2) cout<<"c1≠c2"<<endl;    if (c1>=c2) cout<<"c1≥c2"<<endl;    if (c1<=c2) cout<<"c1≤c2"<<endl;    cout<<endl;    cout<<"c1+c2的数值为：";    c=c1+c2;    cout<<c;  cout<<endl;  cout<<"c1-c2的数值为：";    c=c1-c2;    cout<<c;    cout<<endl;    cout<<"c1*c2的数值为：";    c=c1*c2;    cout<<c;  cout<<endl;  cout<<"c1/c2的数值为：";    c=c1/c2;    cout<<c;   cout<<endl;  cout<<"对c1取反的结果为：";  c=-c1;  cout<<c;  cout<<endl;     
}