1081 检查密码 (15 分)

题目链接

算法分析

用两个变量ap_digit和ap_zm来记录是否有数字和字母出现,然后进行特判并输出就好了.

测试点

测试点2是在考察是否有考虑字符串中含有空格

代码实现

#include<bits/stdc++.h>
using namespace std;int main(){string s;int n;scanf("%d", &n);getline(cin, s);for(int i = 1; i <= n; ++ i){getline(cin, s);int len = s.size();if(len < 6){puts("Your password is tai duan le.");continue;}int ap_digit = 0, ap_zm = 0;for(int j = 0; j < len; ++ j){if(isdigit(s[j])) ap_digit = 1;else if(islower(s[j]) || isupper(s[j])) ap_zm = 1;else if(s[j] == '.') continue;else{ap_digit = ap_zm = 0;break;}}if(ap_digit && ap_zm) puts("Your password is wan mei.");else if(ap_digit && !ap_zm) puts("Your password needs zi mu.");else if(!ap_digit && ap_zm) puts("Your password needs shu zi.");else puts("Your password is tai luan le.");}return 0;
}