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我有一个小脚本，我一直在用Python练习。我很难让我的输入接受if语句的数字和接受小写的字符串。在

我想告诉我的脚本，如果用户输入'99'然后关闭程序。到目前为止，它在我有int(input())的地方工作，但在我有input()的地方就不行了。我做错了什么？还是我无能为力？在

现在我的if语句如下：if choice1 == 99:

break

我是不是应该通过引用把99变成一个字符串？在

也许是这样的：

^{pr2}$

脚本如下：global flip

flip = True

global prun

prun = False

def note_finder(word):

prun = True

while prun == True:

print ('\n','\n','Type one of the following keywords: ','\n','\n', keywords,)

choice2 = input('--> ').lower()

if choice2 == 'exit':

print ('Exiting Function')

prun = False

start_over(input)

elif choice2 == 99: # this is where the scrip doesnt work

break # for some reason it skips this elif

elif choice2 in notes:

print (notes[choice2],'\n')

else:

print ('\n',"Not a Keyword",'\n')

def start_over(word):

flip = True

while flip == True:

print ('# Type one of the following options:\n# 1 \n# Type "99" to exit the program')

choice1 = int(input('--> '))

if choice1 == 99:

break

elif choice1 < 1 or choice1 > 1:

print ("Not an option")

else:

flip = False

note_finder(input)

while flip == True:

print ('# Type one of the following options:\n# 1 \n# Type "99" to exit the program')

choice1 = int(input('--> '))

if choice1 == 99:

break

elif choice1 < 1 or choice1 > 1:

print ("Not an option")

else:

flip = False

note_finder(input)